The second condition fails because in_array()
is case-sensitive, so the program above will display:
Got Irix
Example 2. in_array() with strict example
<?php
$a = array('1.10', 12.4, 1.13);
if (in_array('12.4', $a, TRUE))
echo "'12.4' found with strict check\n";
if (in_array(1.13, $a, TRUE))
echo "1.13 found with strict check\n";
?>
This will display:
1.13 found with strict check
Example 3. in_array() with an array as needle
<?php
$a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array ('p', 'h'), $a))
echo "'ph' is found\n";
if (in_array(array ('f', 'i'), $a))
echo "'fi' is not found\n";
if (in_array('o', $a))
echo "'o' is found\n";
?>
// This will output:
'ph' is found
'o' is found